how to calculate range of Tile for one area with mortar ( Cement and sand).
We will notice here amount|the number|the amount} of tiles within the space of eight meter and five meters except for fixing of tiles we have a tendency to used the cement mortar and that we need to conjointly notice the mortar volume and quantity of cement and cement volume.

NUMBERS OF TILES FOR ONE ROOM
Size of room : Length of Room : L = 8 me , Breadth of Room: B = 5 m
Size of Tile : Length of Tile   L = 30cm   , Breadth of Tile : B = 30cm
Thickness of floor = 25 mm
Total Area of Room = Length of room x breadth of room = 8 x 5 = 40 m2
Now we will Select proportion of Mortar (1:4)
where 1 is Cement and 4 is Sand
Sum of Ratio = 1 + 4 = 5  That is, 6 meters x 10 meters = 60 m2
Now we have to find out the volume of mortar for Tile fixing
Volume of mortar  V = Total Area of Room x thickness of mortar = 40 x 50/100 =  2m3  volume of mortar is Wet volume )

Now Convert Wet volume to Dry Volume
Wet volume x 25 % of wet volume  Dry volume = 2 x 1.25 = 2.25 m3

Now we have to find out Volume of Cement and Sand from Mortar
Volume = Proportion of Cement / Sum of Proportion of mortar  x Dry volume of mortar
Volume = 1 / 5 x 2.25 = 0.45 m3

find out Volume of Cement and Sand from Mortar
Volume of Cement Required = Proportion of Cement / Sum of Proportion of mortar  x Dry volume of mortar
V = 1 / 5 x 2.25 = 0.4 m3
Convert to Cement bags = Volume of Cement / Volume of cement bag
Nos of Cement bags = 0.45 / 0.035 = 12.85 say   13 Nos Cement bags.
Volume of Sand = Proportion of Sand / Sum of Proportion of mortar  x Dry volume of mortar
V of Sand = 4 / 5 x 2.25 = 1.8 m3

NUMBER OF TILES REQUIRED FOR ONE ROOM FLOOR.
Formula: Total Area of floor / Size of One Tile = 40 / 0.3×0.3 = 445 No’s of Tile
Size of Tiles in Centimeters  = 20 x 20 - 30 x 30 - 45 x 45 - 10 x 60 - 10 x 10 - 225 x 45 - 60 x 120
Here in on top of dimension of tiles you'll be able to get within the market and every one these size ar out there within the market and to seek out out hte amount of tiles we tend to use an equivalent formulas for any size of tiles.